A conttrol system with a PD controller is shown in the figure. If the velocity error constant Kv=1000 and the damping ratio ζ=0.5, then the values of KP and KD are
A
KP=100,KD=0.09
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
KP=100,KD=0.9
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
KP=10,KD=0.09
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
KP=10,KD=0.9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is BKP=100,KD=0.9 Kv=lims→0sG(s)H(s) 1000=lims→0s×(KP+KDs)100s(s+10) ⇒KP=100
Now characteristics eq. (1+G(s)H(s))=0 1+(KP+KDs)100s(s+10)=0
Putting KP=100 s2+10s+104+100KDs=0 s2+(10+100KD)s+104=0
Comparing with standard second order eq.
i.e s2+2ζωns+ω2n=0
So, ωn=100;2ζωn=10+100KD
Given,ζ=0.5 2×0.5×100=10+100KD KD=0.9