A convergent beam of light passes through a diverging lens of focal length 0.2 m and comes to focus 0.3 m behind the lens. Find the position of the point at which the beam would converge in the absence of lens.
0.12 m
OP can be taken as the virtual object for the lens whose image is formed at I
Here, f = -0.2m = -20cm
v = 0.3 m = 30 cm
We know that, 1/u = 1/v - 1/f = 1/30 + 1/20
or, 1/u = 50/600
or, u = 12 cm = 0.12m
Thus, if the lens was not there, the rays would have met at a distance 12 cm behind the lens.