A converging lens has a focal length of $50 c m$ . The power of the lens is

+ 5 D

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+ 2 D

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+ 0.5 D

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- 0.5 D

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Solution

The correct option is B $+ 2 D$
The power of lens is $P = 1 / f$ and the unit of it Dioptres (D). Here the focal length f should be in meter.
Here, $f = 50 c m = (50 / 100) m = 0.5 m$
So, $P = + 2 D$

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A converging lens has a focal length of 50cm. The power of the lens is

The correct option is B +2DThe power of lens is P=1/f and the unit of it Dioptres (D). Here the focal length f should be in meter. Here, f=50cm=(50/100)m=0.5mSo, P=+2D

A converging lens has a focal length of $50 c m$ . The power of the lens is

The correct option is B $+ 2 D$
The power of lens is $P = 1 / f$ and the unit of it Dioptres (D). Here the focal length f should be in meter.
Here, $f = 50 c m = (50 / 100) m = 0.5 m$
So, $P = + 2 D$