A converging lens has a focal length of 50 cm. The power of this lens is :
(a) +0.2D
(b) −2.0D
(c) +2.0D
(d) −0.2D

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Solution

(c) +2.0 D

Power = $\frac{1}{Focal length} = \frac{1}{0.5 m} = + 2 D$ .

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A converging lens has a focal length of 50 cm. The power of this lens is : (a) +0.2D (b) −2.0D (c) +2.0D (d) −0.2D

(c) +2.0 D Power = 1Focal length=10.5 m=+2 D.

A converging lens has a focal length of 50 cm. The power of this lens is :
(a) +0.2D
(b) −2.0D
(c) +2.0D
(d) −0.2D

(c) +2.0 D

Power = $\frac{1}{Focal length} = \frac{1}{0.5 m} = + 2 D$ .