A converging lens has a focal length of 50 mm. What is the power of the lens?

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Solution

Focal length, $f = 50 m m = 0.05 m$

Power $= \frac{1}{f} = \frac{1}{0.05} = 20 D$

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A converging lens has a focal length of 50 mm. What is the power of the lens?

Focal length, f=50 mm=0.05 m Power =1f=10.05=20 D

Focal length, $f = 50 m m = 0.05 m$

Power $= \frac{1}{f} = \frac{1}{0.05} = 20 D$