A converging lens has focal length of 50 mm. What is the power of the lens?

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Solution

Power of a lens is given by:

Power (P) = $\frac{1}{f}$

∴ P = $\frac{1}{50 \times 10^{- 3}}$ = $\frac{1000}{50}$ = 20 D.

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A converging lens has focal length of 50 mm. What is the power of the lens?

Power of a lens is given by: Power (P) = 1f ∴ P = 150×10-3 = 100050= 20 D.

Power of a lens is given by:

Power (P) = $\frac{1}{f}$

∴ P = $\frac{1}{50 \times 10^{- 3}}$ = $\frac{1000}{50}$ = 20 D.