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Question

A convex lens forms a real image with magnification m1 on a screen. Now, the screen is moved by a distance x and the object is also moved so as to obtain a real image with magnification m2(>m1) on the screen. Then, the focal length of the lens is

A
[m1m2]x
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B
[m2m1]x
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C
x(m2m1)
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D
x(m2m1)
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Solution

The correct option is C x(m2m1)
The magnification m=vf1 in case of displacement method. case 1V=Vm1=Vf1V=(m1+1)f
caseil v=v+xm2=v+xf1v=(m2+1)fx(m1+1)f=(m2+1)fxm1f+f=m2f+fxf=xm2m1

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