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Question

A convex lens forms an image of an object on a screen. The height of the image is 9 cm. The lens is now displaced until an image is again obtained on the screen. The height of this image is 4 cm. The distance between the object and the screen is 90cm.


A
The distance between the two positions of the lens is 30cm.
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B
The distance of the object from the lens in its first position is 36cm.
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C
The height of the object is 6cm.
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D
The focal length of the lens is 21.6 cm.
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Solution

The correct options are
B The distance of the object from the lens in its first position is 36cm.
C The height of the object is 6cm.
D The focal length of the lens is 21.6 cm.
For the two real images u and v get interchanged
vu=9h0 and uv=4h0
36h20=1h0=6 cm
Also v+u=90 and 6u=9v
v=9v6=90
v=54 and u=36
The distance between the two lens positions is v - u = 28 cm
Also 1v1u=1f
1541(36)=1f
f=21.6 cm

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