A convex lens is used to form real image of an object on a screen. It is observed that even when the positions of the object and that screen are fixed are two position of the lens to form real images. If the heights of the images are $4 c m$ and $9 c m$ respectively the height of the object is

2.25 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6.00 c m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6.50 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

36.00 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $6.00 c m$
As we know,
$O = \sqrt{I_{1} I_{2}} \Rightarrow O = \sqrt{4 \times 9} = 6 c m$

Suggest Corrections

Similar questions

Q. A convex lens forms a real image

9 c m

long on a screen. Without altering the position of the object and the screen, the lens is displaced and we get again a real image

4 c m

long on the screen. Then the length of the object is-

Q. A convex lens makes a real image

4 c m

long on a screen. When the lens is shifted to a new position without disturbing object or the screen, we again get a real image on the screen which is

9 c m

long. The length of the object must be :

Q. A convex lens forms a real image of an object for its two different positions on a screen. If height of the image in both the cases be 8 cm and 2 cm, then height of the object is

Q. A convex lens when placed in the first position forms a real image of an object on a fixed screen. The distance between the object and the screen is

75 cm

. On displacing the lens from first position by

25 cm

to the second position, again a real image is formed on the screen. Then the focal length of the lens is

A convex lens forms an image of an object on a screen. The height of the image is 9 cm. The lens is now displaced until an image is again obtained on the screen. The height of this image is 4 cm. The distance between the object and the screen is 90cm.

Join BYJU'S Learning Program

A convex lens is used to form real image of an object on a screen. It is observed that even when the positions of the object and that screen are fixed are two position of the lens to form real images. If the heights of the images are 4 cm and 9 cm respectively the height of the object is

The correct option is B 6.00 cmAs we know,O=√I1I2⇒O=√4×9=6 cm

A convex lens is used to form real image of an object on a screen. It is observed that even when the positions of the object and that screen are fixed are two position of the lens to form real images. If the heights of the images are $4 c m$ and $9 c m$ respectively the height of the object is

The correct option is B $6.00 c m$
As we know,
$O = \sqrt{I_{1} I_{2}} \Rightarrow O = \sqrt{4 \times 9} = 6 c m$