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Question

A convex lens of 2 D power is joined with a concave mirror of 1 D power. Equivalent power of instrument will be


A
3D
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B
+3D
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C
5D
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D
+5D
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Solution

The correct option is D 3D
Power of the convex lens = 2D
Power of the concave mirror = 1D
The equivalent power of the combination of a convex lens and a concave mirror is given by the formula
Pequivalent=Pmirror2Plens
Substituting the values in the formula,
Pequivalent=12(2)
Pequivalent=14
Pequivalent=3D
The equivalent power of the instrument will be -3D.


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