A convex lens of focal length 15 cm is placed on a plane mirror. An object is placed at 30 cm from the lens. The image will be

real, at 30 cm in front of the mirror

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real, at 30 cm behind the mirror

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real, at 10 cm in front of the mirror

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virtual, at 10 cm behind the mirror

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Solution

The correct option is A real, at 10 cm in front of the mirror
$\frac{1}{F} = \frac{1}{f_{1}} + \frac{1}{f_{m}} + \frac{1}{f_{1}} = \frac{2}{f_{1}} + \frac{1}{\infty} \Rightarrow F = \frac{15}{2} c m$
$\frac{2}{15} = \frac{1}{30} + \frac{1}{v}, v = 10 c m .$
$∴$ image is real , 10 cm in front of mirror.

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A convex lens of focal length 15 cm is placed on a plane mirror. An object is placed at 30 cm from the lens. The image will be

The correct option is A real, at 10 cm in front of the mirror1F=1f1+1fm+1f1=2f1+1∞⇒F=152cm215=130+1v,v=10cm.∴ image is real , 10 cm in front of mirror.