Given,
The focal length of the convex lens = 25 cm = 0.25 m
We know,
Power=1f
Or, Power=10.25=4D
Power of the convex lens P1=4D
The focal length of the concave lens = -10 cm = -0.1 m
We know,
Power=1f
Or, Power=1−0.1=−10D
Power of the concave lens P2=−10D
Now,
Power of the combination = P1+P2=(1−10)=−6D
Hence , the power of the combination is -6 D.