The correct option is C −1.67 D
Given:
Focal length of convex lens, f1=30 cm
Focal length of concave lens, f2=−20 cm
(Using new cartesian sign conventions, focal length of convex lens is positive and that of concave lens is negative)
Power of a lens in dioptre is reciprocal of its focal length in metre.
Power of convex lens, P1=1f1
Power of concave lens, P2=1f2
Power of combination of lenses in contact is the sum of individual powers. Hence, power of the effective lens is:
P=P1+P2
P=1f1+1f2
P=130/100+1−20/100
P=−1.67 D