A convex lens of focal length $f$ is cut into two halves as shown. Light rays parallel to the principal axis are incident on one half of the lens ( say $L_{1}$ ). This will form an image at :

f

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\frac{f}{2}

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2 f

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\frac{f}{4}

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Solution

The correct option is A $f$
If a convex lens is cut horizontally from optical axis then the radius of curvature will remain same.
As focal length is given by $\frac{1}{f} = (μ - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})$ (len's maker formula)
As $R_{1}$ and $R_{2}$ do not changes. So, there will be no change in focal length, it will remain f.
Hence, option A is correct.

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A convex lens of focal length f is cut into two halves as shown. Light rays parallel to the principal axis are incident on one half of the lens ( say L1 ). This will form an image at :

A convex lens of focal length $f$ is cut into two halves as shown. Light rays parallel to the principal axis are incident on one half of the lens ( say $L_{1}$ ). This will form an image at :