Question

A convex mirror has a focal length f. A real object is placed at a distance of $\frac{f}{2}$ from the pole. Find out the position, magnification and nature of the image.

Answer 1

Object distance $u=-\frac{f}{2}$

Focal length of convex mirror is $f$.

Using mirror image : $\frac{1}{v}+\frac{1}{u}=\frac{1}{f}$

Or $\frac{1}{v}+\frac{1}{-\left(f/2\right)}=\frac{1}{f}$

$⟹v=\frac{f}{3}$

Magnification $m=\frac{-v}{u}=\frac{-\left(f/3\right)}{-f/2}=\frac{2}{3}$

The image formed is virtual and erect and diminished.