Question

A convex mirror of radius of curvature $1.6m$ has an object placed at a distance of $1m$ from it. The image is formed at a distance of :

• A. $\frac{18}{3}m$ behind the mirror
• B. $\frac{18}{3}m$ infront of the mirror
• C. $\frac{4}{9}m$ behind the mirror
• D. $\frac{4}{9}m$ infront of the mirror

Answer 1

The correct option is C $\frac{4}{9}m$ behind the mirror

Given, $f=\frac{1.6}{2}=0.8m$ and $u=-1m$

$\frac{1}{f}=\frac{1}{v}-\frac{1}{u}$

$\frac{1}{v}=\frac{1}{0.8}-\frac{1}{-1}=\frac{10}{8}+1=\frac{9}{4}$

$\Rightarrow v=\frac{4}{9}m$