The correct option is A v=1.15 m, virtual Image
Radius of curvature =3 m
We know that
Focal length f=R2=32=+1.5 m
[Since the focus of convex mirror is behind the mirror, the focal length will be positive].
Now,
Bus (object) is placed in front of the mirror.
∴ Object distance will be negative
Object distance =u=−5 m
Let the image distance be ′v′.
Then, v=ufu−f
⇒v=(−5)(+1.5)−5−1.5≈+1.15 m
In a convex mirror, virtual image is formed for a real object.
So, option (a) is correct.