The correct option is A 2.5
On using the sign conventions, we get,
Object distance, u = –5 m (always negative)
Radius of curvature, R = 10 m
Focal length, f = R/2 = 10/2 = 5 m
By applying the mirror formula, we get,
1v+1u=1f
1v+1−5=15⇒1v=15+15
v=2.5m
The image is formed 2.5 m behind the mirror.