A conveyor belt is moving at a constant speed of 2m/s, a box is gently dropped on it. The coefficient of friction between them is 0.5. The distance that the box will move relative to belt before coming to rest on it (taking g=10ms−2), is:
A
1.2m
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B
0.6m
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C
zero
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D
0.4m
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Solution
The correct option is D0.4m a=μg=5 v2=u2+2as 0=22+2×(5)s s=−25 with respect to belt or distance =0.4m.