You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Geometrical Isomerism in Square Planar Geometry

A coordinatio...

Question

A coordination complex compound of cobalt has the molecuar formula containing five ammonia molecules, one nitro group and two chlorine atoms for one cobalt atom. One mole of this compound produces three moles of ions in an aqueous solution. On the addition of silver nitrate, two moles of $A g C l$ are precipitated. The ionic formula for this complex would be:

[C o (N H_{3})_{5} (N O_{2})] C l_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[C o (N H_{3})_{5} C l] (C l) (N O_{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[C o (N H_{3})_{4} (N O_{2}) C l] (N H_{3}) (C l)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[C o (N H_{3})_{5}] (N O_{2}) (C l)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $[C o (N H_{3})_{5} (N O_{2})] C l_{2}$
As the complex gives two moles of $A g C l$ ppt. with $A g N O_{3}$ solution, the complex must have two ionisable $C l$ atoms. Hence, the possible formula of the complex which gives three moles of ions may be $[C o (N H_{3})_{5} N O_{2}] C l_{2}$ .

$[C o (N H_{3})_{5} N O_{2}] C l_{2} \to [C o (N H_{3})_{5} N O_{2}]^{2 +} + 2 C l^{-}$

Suggest Corrections

Similar questions

Q. A complex compound of cobalt has molecular formula containing five

N H_{3}

molecules, one nitro group and two chlorine atom for one cobalt atom. One mole of this compound produces three moles of ion in aqueous solution. On reaction with excess of

A g N O_{3}

solution two moles of

A g C l

get precipitated. The ionic formula of the compound is :

Q. A compound has the empirical formula

C o C l_{3} .5 N H_{3}

. When an aqueous solution of this compound is mixed with excess of silver nitrate, 2 moles of

A g C l

precipitate out per mole of compound. On reaction with excess of HCl, no

N H_{4}^{+}

is detected. Hence, the compound is :

Q. When 0.01 mole of a cobalt complex is treated with excess silver nitrate solution, 4.305 g silver chloride is precipitated. The formula of the complex is:

One mole of the complex compound $C o (N H_{3})_{5} C l_{3}$ gives three moles of ions on dissolution in water. One mole of the same complex reacts with two moles of $A g N O_{3}$ solution to yield two moles of $A g C l (s)$ . The structure of complex is:

Q. One pink solid (X) has the formula

C o C l_{3} .5 N H_{3} . H_{2} O . A

solution of this salt (X) in water is also pink and precipitates 3 mole AgCl on treatment with silver nitrate solution. When the pink solid (X) is heated, it loses

1 m o l e H_{2} O

to yield a purple solid (Y) with the same molar ratio of

N H_{3} : C l : C o

. The purple solid releases two of its chlorides rapidly on dissolution and after treatment with

A g N O_{3}

solution. The coordination number of cobalt in complexes (X) and (Y) is six. The IUPAC name of pink (X) and purple (Y) complexes respectively are:

Join BYJU'S Learning Program

The correct option is A [Co(NH3)5(NO2)]Cl2As the complex gives two moles of AgCl ppt. with AgNO3 solution, the complex must have two ionisable Cl atoms. Hence, the possible formula of the complex which gives three moles of ions may be [Co(NH3)5NO2]Cl2. [Co(NH3)5NO2]Cl2→[Co(NH3)5NO2]2++2Cl−