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Question

A coordination compound CrCl3.4H2O gives white precipitate of AgCl with AgNO3. The molar conductance of the compound corresponds to two ions. The structural formula of the compound is:

A
[Cr(H2O)4Cl3]
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B
[Cr(H2O)3Cl3]H2O
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C
[Cr(H2O)4Cl2]Cl
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D
[Cr(H2O)4Cl]Cl2
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Solution

The correct option is C [Cr(H2O)4Cl2]Cl
[Cr(H2O)4Cl3] and [Cr(H2O)3Cl3]H2O will not give any ion in the solution. [Cr(H2O)4Cl]Cl2 will give three ions in the solution.
[Cr(H2O)4Cl]Cl2[Cr(H2O)4Cl]2++2Cl
[Cr(H2O)4Cl2]Cl will give two ions in the solution.
[Cr(H2O)4Cl2]Cl[Cr(H2O)4Cl2]++Cl
Chloride ion will react with silver ion (from silver nitrate) to form silver chloride precipitate.
Ag++ClAgCl

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