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Capacitance of Parallel Plate Capacitor

A copper cons...

Question

A copper constantan thermocopule with $0^{o} C$ reference junction temperature was found to have linear calibration between $0^{o} C$ and $400^{o} C$ as shown in figure.

The temperature of the hot junciton $(i n^{o} C)$ if the indicated emf is $10 m V$ with cold juction temperature of $10^{o} C$ is
200

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Solution

The correct option is A 200
$First we find correction factor (E_{C}) for cold junction 10^{o} C$

$E_{c} = \frac{20 m V}{400^{o} C} \times 10^{o} C = 0.5 m V$

$\frac{E - E_{C}}{T - T_{C}} = \frac{20 m V}{400^{o} C}$ $(From given graph)$

$\frac{10 m V - 0.5 m V}{T - 10} = \frac{20 m V}{400}$

$T - 10 = 9.5 \times \frac{400}{20}$

$= 95 \times 2$

$T = 10 + (190)$

$T = 200^{o} C$

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