The correct option is D At steady state the rate of change of temperature (dTdt) for all sections will be equal to zero.
Initially due to temperature difference ΔT=100∘ C, maximum amount of heat current (dQdt) will enter through section A but the metal will absorb some amount of heat during flow of heat current from A to C.
Thus the value of heat current (dQdt) leaving section C will be minimum.
∴ option (b) is correct.
At steady statement the rate of heat flow (heat current ) is constant.
⇒dQdt=kA∣∣∣dTdx∣∣∣
or ∣∣∣dTdx∣∣∣=(dQdt)kA
[(∵dQdt=constant & k= constant for material)]
∣∣∣dTdx∣∣∣∝1A
Hence temperature gradient is inversity proportional to area.
∵ Area of cross - section at section B is minimum
⇒∣∣∣dTdx∣∣∣ is maximum at section B.
At steady state the rate of heat accumulation at any cross -section is zero.
Hence, the rate of change of temperature w.r.t time at any cross-section will be zero.
⇒dTdt=0
∴ option (c) & (d) are correct.
Why this question?Tip: At steady state the rate of heat outflowand heat inflow at any cross-section is equal,hence no heat accumulation occuss at steady state.