A copper rod of diameter 1 cm and length 8 cm is drawn into a wire of length 18 m of uniform thickness. Find the thickness of the wire.
0.67mm(approx..)
The volume of the rod = π×(12)2×8cm3=2πcm3
The length of the new wire of the same volume = 18 m = 1800 cm
If r is the radius (in cm) of cross-section of the wire, its volume = π×r2×1800cm3
Therefore, π×r2×1800=2π
i.e., r2=1900
i.e., r=130
So, the diameter of the cross section, i.e., the thickness of the wire is 115cm,
i.e., 0.67mm (approx.).