wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A copper rod of length 1.0 m is clamped at its middle point. Find the frequencies between 20 Hz and 20,000 Hz at which standing longitudinal waves can be set up in the rod. The speed of sound in copper is 3.8 kms1


A

n × 1.9 kHz

n=1,2,3.....10

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

n × 3.1 kHz

n=1,2,3,4,5,6

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

n × 5 kHz

n=1,2,3,4

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

n × 1.9 kHz

n=1,2,3.....10


Length of wire = 1.0 m

For fundamental frequency λ2=l

λ = 2l = 2 × L = 2m

Here given v = 3.8 kms1= 3800 ms

We know v = fλ f=38002=1.9 kHz.

So standing wave frequency between 20 Hz and 20 kHz which will be heard are

f= n × 1.9 kHz
where n = 1, 2, 3,..... 9, 10


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
What Sound Really Is
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon