Question

A copper rod with length $1.4$m and area of cross-section of $2c{m}^2$ is fastened to a steel rod with length L and cross-sectional area $1$ $c{m}^2$. The compound rod is subjected to equal and opposite pulls of magnitude $6.00\times {10}^4$N at its ends.
What is stress in each rod?

Answer 1

${\sigma }_C=\frac{F}{A_C}=\frac{6\times {10}^4}{2\times {10}^{-4}}=3\times {10}^{8}N/m^2$

and ${\sigma }_S=\frac{F}{A_S}=\frac{6\times {10}^4}{1\times {10}^{-4}}=6\times {10}^{8}N/m^2$.