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Question

A copper wire of cross- sectional area 0.01 cm2 is under a tension of 20 N. Find the decrease in the cross-sectional area. Young modulus of copper = 1.11×Nm2 and Poisson ratio = 0.32 \)


Solution

A = 0.01cm2

   =  106m2

T = 20 N, 

Y = 1.1×1011Nm2

We know that, Y =FLAΔL

ΔL=FAY

 = 20106×1.1×1011×18.18×105

 d=ΔDDΔLL=0.32

So, ΔDD=(0.32)×KLL

= 32×(18.18)×105=5.81×105

Again, ΔAA=2Δrr

ΔA=2Δrr

 DeltaA=2×(5.8×105)×(0.01)

 = 1.16×105cm2


Physics

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