A copper wire of length 10 m and radius 10-2 - - m has electrical resistance of 10 - The current density in the wire for an electric field strength of 10 V - m is-

Given L=10 m, r=10^ 2√(π)m R=10 Ω, E=10 V / m Current density J= ? We know J=σ E=Eρ J=E LR A=10 × 1010 ×π×10^ 4π J=10^5 A / m^2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Current Density Vector

A copper wire...

Question

A copper wire of length $10 m$ and radius $(10^{- 2} / \sqrt{π}) m$ has electrical resistance of $10 Ω$ . The current density in the wire for an electric field strength of $10 (V / m)$ is:

10^{6} A / m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10^{5} A / m^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10^{- 5} A / m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10^{4} A / m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $10^{5} A / m^{2}$
Given $L = 10 m, r = \frac{10^{- 2}}{\sqrt{π}} m$

$R = 10 Ω, E = 10 V / m$

Current density $J =$ ?

We know $J = σ E = \frac{E}{ρ}$

$J = \frac{E L}{R A} = \frac{10 \times 10}{10 \times π \times \frac{10^{- 4}}{π}}$

$J = 10^{5} A / m^{2}$

Suggest Corrections

100

Similar questions

A wire has a length of 2.0 m and a resistance of 5.0 $Ω$ Find the electric field existing inside the wire if it carries a current of 10 A.

Q. An aluminium wire carrying a current has diameter 0.84 mm. The electric field in the wire is 0.49

V / m

. What is,
(a) the current carried by the wire?
(b) the potential difference between two points in the wire 12.0 m apart?

Specific resistance of aluminum is $2.75 \times 10^{8} Ω - m$ .

Calculate the electric field in a copper wire of cross-sectional are 2.0 $m m^{2}$ carrying a current of 1 A. The resistivity of copper = 1.7 $\times 10^{- 8} Ω m .$

Q. A copper wire of cross-sectional area

2.0 m m^{2}

, resistivity =

1.7 \times 10^{- 8} Ω m

, carries a current of 1 A. The electric field in the copper wire is:

Q. In an electrical cable, there is a single copper wire of radius

6 m m

. Its resistance is

10 Ω

. The single wire in the cable is replaced by five different insulated copper wires with the radius of

2 m m

for each wire. The new resistance of the cable is:

Join BYJU'S Learning Program

A copper wire of length 10 m and radius (10−2/√π)m has electrical resistance of 10 Ω. The current density in the wire for an electric field strength of 10( V/m) is:

The correct option is B 105 A/m2Given L=10 m,r=10−2√πm R=10 Ω,E=10 V/m Current density J= ? We know J=σE=Eρ J=ELRA=10×1010×π×10−4π J=105 A/m2

A copper wire of length $10 m$ and radius $(10^{- 2} / \sqrt{π}) m$ has electrical resistance of $10 Ω$ . The current density in the wire for an electric field strength of $10 (V / m)$ is:

The correct option is B $10^{5} A / m^{2}$
Given $L = 10 m, r = \frac{10^{- 2}}{\sqrt{π}} m$

$R = 10 Ω, E = 10 V / m$

Current density $J =$ ?

We know $J = σ E = \frac{E}{ρ}$

$J = \frac{E L}{R A} = \frac{10 \times 10}{10 \times π \times \frac{10^{- 4}}{π}}$

$J = 10^{5} A / m^{2}$