A copper wire of length 10 m and radius 10-2 - - m has electrical resistance of 10 - The current density in the wire for an electric field strength of 10 V - m is-

Given L=10 m, r=10^ 2√(π)m R=10 Ω, E=10 V / m Current density J= ? We know J=σ E=Eρ J=E LR A=10 × 1010 ×π×10^ 4π J=10^5 A / m^2 ...

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Byju's Answer

Standard XII

Physics

Current Density Vector

A copper wire...

Question

A copper wire of length $10 m$ and radius $(10^{- 2} / \sqrt{π}) m$ has electrical resistance of $10 Ω$ . The current density in the wire for an electric field strength of $10 (V / m)$ is:

10^{6} A / m^{2}

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10^{5} A / m^{2}

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10^{- 5} A / m^{2}

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10^{4} A / m^{2}

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Solution

The correct option is B $10^{5} A / m^{2}$
Given $L = 10 m, r = \frac{10^{- 2}}{\sqrt{π}} m$

$R = 10 Ω, E = 10 V / m$

Current density $J =$ ?

We know $J = σ E = \frac{E}{ρ}$

$J = \frac{E L}{R A} = \frac{10 \times 10}{10 \times π \times \frac{10^{- 4}}{π}}$

$J = 10^{5} A / m^{2}$

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A copper wire of length 10 m and radius (10−2/√π)m has electrical resistance of 10 Ω. The current density in the wire for an electric field strength of 10( V/m) is:

The correct option is B 105 A/m2Given L=10 m,r=10−2√πm R=10 Ω,E=10 V/m Current density J= ? We know J=σE=Eρ J=ELRA=10×1010×π×10−4π J=105 A/m2

A copper wire of length $10 m$ and radius $(10^{- 2} / \sqrt{π}) m$ has electrical resistance of $10 Ω$ . The current density in the wire for an electric field strength of $10 (V / m)$ is:

The correct option is B $10^{5} A / m^{2}$
Given $L = 10 m, r = \frac{10^{- 2}}{\sqrt{π}} m$

$R = 10 Ω, E = 10 V / m$

Current density $J =$ ?

We know $J = σ E = \frac{E}{ρ}$

$J = \frac{E L}{R A} = \frac{10 \times 10}{10 \times π \times \frac{10^{- 4}}{π}}$

$J = 10^{5} A / m^{2}$