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Magnetic Field Due to Circular Current Carrying Conductor

A copper wire...

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A copper wire of resistance 10 ohm is in the form of a perfect circle. Two points A and B on it are connected to a battery of emf 5 V and internal resistance 0.5 ohm . The two segments of the circle have lengths in the ratio 2 : 3. The net magnetic induction at the centre of the circle is

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Q. A wire of resistance 10 ohm is bent to form a circle. P & Q are points on the circumference of the circle dividing it onto a quadrant and are connected to a battery of 3 volt an internal resistance of 1 ohm as shown on the figure. The current in the two parts of the circle are

Q. A wire of resistance

10 Ω

is bent to form a circle. P and Q are points on the circumference of the circle dividing it into a quadrant and are connected to a battery of

3 V

and internal resistance

1 Ω

as shown in the figure. The currents in the two parts of the circle are

10 m

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ohm is connected in series with a battery of emf

2 V

(no internal resistance) and a resistance of

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ohm. The potential gradient along the wire is:

Q. The length of uniform wire of resistance

10 Ω

is bent into a circle and two points at a quarter of circumference apart, are connected to a battery of e.m.f.

2.3 V

and internal resistance

1 Ω

i_{1}

i_{2}

Q. Two batteries one of emf 3 V, internal resistance 1 ohm and the other of emf 15 V, internal resistance 2 ohm are connected in series with a resistance R as shown. If the potential difference between a and b is zero, the resistance of R in ohms is

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Magnetic Field Due to Circular Current Carrying Conductor

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