1
Question
A copper wire of resistivity 1.6 ×10-8ohm metre has a cross sectional area of 20×10-4cm2. Calculate the length of the wire required to make a 10 ohm coil.
A copper wire of resistivity 1.6 ×10-8ohm metre has a cross sectional area of 20×10-4cm2. Calculate the length of the wire required to make a 10 ohm coil.
Open in App
Solution
here
rho,(resistivity) = 1.6×10^-8
area = 20×10^-4cm2
= 20*10^-8 m2
r,resistance = 10
length,l = ?
we use formulae
r = (rho ×l) / a
10 = (1.6 ×10^-8 ×l) / 20×10^-8
(on dividing 1.6×10^-8 by 20×10^-8 we get = 0.08)
10 = 0.08 × l
l×0.08 = 10
l= 10/0.08
l = 1000/ 8
l = 125m
thus required length of wire is 125 m
here
rho,(resistivity) = 1.6×10^-8
area = 20×10^-4cm2
= 20*10^-8 m2
r,resistance = 10
length,l = ?
we use formulae
r = (rho ×l) / a
10 = (1.6 ×10^-8 ×l) / 20×10^-8
(on dividing 1.6×10^-8 by 20×10^-8 we get = 0.08)
10 = 0.08 × l
l×0.08 = 10
l= 10/0.08
l = 1000/ 8
l = 125m
thus required length of wire is 125 m
Suggest Corrections
35
Similar questions
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
