A copper wire of resistivity 1.6X10 raised to power -2 ohm meter has a cross sectional area of 20X10 raised to power -8 cm .calculate the length of this wire to make the resistance of 10 ohm

Open in App

Solution

Dear student

$R e s i s \tan c e o f t h e w i r e i s R = \frac{ρ L}{A} L = \frac{R A}{ρ} = \frac{10 \times 20 \times 10^{- 8}}{1.6 \times 10^{- 2}} = \frac{2 \times 10^{- 6}}{1.6 \times 10^{- 2}} = \frac{20}{16} \times 10^{- 4} = 1.25 \times 10^{- 4} m R e g a r d s$

Suggest Corrections

Similar questions

Q. A copper wire of resistivity

1.6 \times 10^{- 8}

ohms metre has a cross-sectional area of

10 \times 10^{- 4} c m^{2}

. Calculate the length of this wire required to make a

10

ohm coil.

1.A copper wire has diameter 0.5mm & reactivity of 1.6*10 to the power -8 ohm m.what will be the length of this wire to make its resistance 10 ohm ? How much does the resistance charge if the diameter is doubled?

Q. Copper wire of length

3 m

and the area of cross section

1.7 \times 10^{- 6} m^{2}

has a resistance of

3 \times 10^{- 2} m^{2}

ohms. Calculate the resistivity of copper?

Join BYJU'S Learning Program

A copper wire of resistivity 1.6X10 raised to power -2 ohm meter has a cross sectional area of 20X10 raised to power -8 cm .calculate the length of this wire to make the resistance of 10 ohm

Dear student Resistance of the wire is R=ρLAL=RAρ=10×20×10-81.6×10-2=2×10-61.6×10-2=2016×10-4=1.25×10-4 mRegards

Dear student

$R e s i s \tan c e o f t h e w i r e i s R = \frac{ρ L}{A} L = \frac{R A}{ρ} = \frac{10 \times 20 \times 10^{- 8}}{1.6 \times 10^{- 2}} = \frac{2 \times 10^{- 6}}{1.6 \times 10^{- 2}} = \frac{20}{16} \times 10^{- 4} = 1.25 \times 10^{- 4} m R e g a r d s$