A cord is used to lower vertically a block of mass M by a distance d with constant downword acceleration g2 work done by the cord on the block is
A
−Mgd2
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B
Mgd4
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C
−3Mgd4
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D
Mgd
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Solution
The correct option is A−Mgd2 Work done=F.s=(Mg2)d
Here we are asked the work done by the cord on the block. So a negative sign will come as the tension force will develop in the upward direction in the cord and the displacement is in downward direction