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Question

A cottage industry manufactures pedestal lamps and wooden shades, each requiring the use of a grinding/cutting machine and a sprayer. It takes 2 hours on grinding/cutting machine and 3 hours on the sprayer to manufacture a pedestal lamp. It takes 1 hour on the grinding/cutting machine and 2 hours on the sprayer to manufacture a shade. On any day, the sprayer is available for at least for at the most 20 hours and the grinding/cutting machine for at the most 12 hours. The profit from the sale of a lamp is Rs.5 and that from a shade is Rs. 3 . Assuming that the manufacturer can sell all the lamps and shades that the produces , how should he schedule his daily production in order to maximise his profit?

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Solution

Let the cottage industry manufacture x pedestal lamps and y wooden shades. Therefore, x0 and y0
The given information can be compiled in a table as follows.

Lamps Shades Availability
Grinding/Cutting Machine (h)
2 1 12
Sprayer3
2 20
The profit on a lamp is Rs.5 and on the shades is Rs.3. Therefore, the constraints are
2x+y12
3x+2y20
Total profit Z=5x+3y
The mathematical formulation of the given problem is
Maximise Z=5x+3y.........(1)
subject to the constraints
2x+y12.......(2)
3x+2y20.....(3)
x,y0........(4)
The feasible region determined by the system of constraints is as shown.
The corner points are A(6,0),B(4,4) and C(0,10)
The values of Z at these corner points are as follows
Corner point Z=5x+3y
A(6,0) 30
B(4,4) 32 Maximum
C(0,10) 30
The maximum value of Z is 32 at (4,4)
Thus, the manufacturer should produce 4 pedestal lamps and 4 wooden shades to maximise his profits.
458096_423041_ans_68e81871b1c04105941f101ce7d41ef9.png

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