Let the cottage industry manufacture
x pedestal lamps and
y wooden shades. Therefore,
x≥0 and
y≥0The given information can be compiled in a table as follows.
| Lamps | Shades | Availability |
Grinding/Cutting Machine (h)
| 2 | 1 | 12 |
Sprayer | 3
| 2 | 20 |
The profit on a lamp is Rs.
5 and on the shades is Rs.
3. Therefore, the constraints are
2x+y≤123x+2y≤20Total profit
Z=5x+3yThe mathematical formulation of the given problem is
Maximise
Z=5x+3y.........(1)subject to the constraints
2x+y≤12.......(2)3x+2y≤20.....(3)x,y≥0........(4)The feasible region determined by the system of constraints is as shown.
The corner points are
A(6,0),B(4,4) and
C(0,10)The values of
Z at these corner points are as follows
Corner point | Z=5x+3y |
|
A(6,0) | 30 |
|
B(4,4) | 32 | → Maximum |
C(0,10) | 30 |
|
The maximum value of
Z is
32 at
(4,4)Thus, the manufacturer should produce
4 pedestal lamps and
4 wooden shades to maximise his profits.