A cottage industry produces a certain number of articles in a day. It was observed on a particular day that the cost of production of each article (in ₹) was 7 more than twice the number of articles produced on that day. Find the number of articles produced, if the total cost of production on that day was ₹ 114.
Let the number of articles produced =x
Given that the cost of production of each article (in ₹) was 7 more than twice the number of articles produced on that day.
So that the cost of production of each article =₹(2x+7)
Given that If the total cost of production on that day was ₹ 114.
So that production cost = ₹ 114
⇒x(2x+7)=114
⇒2x2+7x–114=0
For a quadratic equation ax2+bx+c,
x=−b±√b2−4ac2a
Here a=2,b=7 and c=−114
So, x=−7±√(7)2−4×2×−1142×2
x=−7±√9612=−7±314
x=6 or x=−9.5
x cannot be a negative value. So x=6
Hence, no. of articles produced = 6