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Question

A cottage industry produces a certain number of articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was Rs 90, find the number of articles produced.

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Solution

Let the number of articles produced = x

Given that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day.

So that the cost of production of each article = Rs 2x + 3

Given that If the total cost of production on that day was Rs 90

So that production cost = Rs 90

x(2x + 3) = 90

2 x2 + 3x – 90 = 0

Factorizing the above equation,

2x2-12x+15x -90=0

2x(x-6)+15(x-6)=0

(2x+15)(x-6)=0

x=-152 and x=6 are the roots

But no. of objects cannot be negative.

Hence, No. of articles = 6


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