Question

A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the cost of production was 750. If $x$ denotes the number of toys produced that day, then form the quadratic equation to find $x$.

Answer 1

Let the number of toys produced on a particular day be $x$.

Given: The cost of production of each toy (in rupees) was found to be $55$ minus the number of toys produced on that particular day

Therefore,

Cost of production of each toy on that particular day $=Rs.(55-x)$

$\therefore$ Total cost of production on that particular day for $x$ number of toys $=Rs.x(55-x)$

Also, it is given that on that particular day, the total cost of production was $Rs.750$.

Therefore,

$x(55-x)=750$

$55x-x^2=750$

$\Rightarrow x^2-55x+750=0$

Hence the quadratic equation to find out the no. of toys produced on that particular day is $x^2-55x+750=0$.