A couple consisting of two forces F1 and F2 each equal to 5N is acting at the rim of a disc of mass 2kg and radius 0.5m for 5s. Initially, the disc is at rest, the final angular momentum of the disc is
A
15Nm-s
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B
20Nm-s
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C
25Nm-s
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D
30Nm-s
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Solution
The correct option is C25Nm-s Torque acting on disc is, τ=F1r+F2r=5×12+5×12=5Nm From angular impulse momentum theorem, 5∫0τdt=Lf−Li ⇒5×5=Lf−0⇒Lf=25Nm-s