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Question

A couple consisting of two forces F1 and F2 each equal to 5 N is acting at the rim of a disc of mass 2 kg and radius 0.5 m for 5 s. Initially, the disc is at rest, the final angular momentum of the disc is

A
15 Nm-s
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B
20 Nm-s
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C
25 Nm-s
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D
30 Nm-s
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Solution

The correct option is C 25 Nm-s
Torque acting on disc is,
τ=F1r+F2r=5×12+5×12=5 Nm
From angular impulse momentum theorem,
50τdt=LfLi
5×5=Lf0Lf=25 Nm-s

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