A couple of 20 N-m is needed to rotate a steering wheel. What would be the magnitude of each force if the steering wheel’s diameter is 80 cm?

12.5 N

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25 N

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50 N

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6.25 N

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Solution

The correct option is B 25 N
Given,
Couple = $20 N m$
Diameter = $80 c m = 0.8 m$

Couple = Force × Diameter
$20 N m$ = $F \times 0.8 m$
$F = 25 N$

Hence, the magnitude of each force on the steering wheel should be $25 N$ .

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A couple of 20 N-m is needed to rotate a steering wheel. What would be the magnitude of each force if the steering wheel’s diameter is 80 cm?

The correct option is B 25 N Given, Couple = 20 Nm Diameter = 80 cm=0.8 m Couple = Force × Diameter 20 Nm = F×0.8 m F=25 N Hence, the magnitude of each force on the steering wheel should be 25 N.

The correct option is B 25 N
Given,
Couple = $20 N m$
Diameter = $80 c m = 0.8 m$

Couple = Force × Diameter
$20 N m$ = $F \times 0.8 m$
$F = 25 N$

Hence, the magnitude of each force on the steering wheel should be $25 N$ .