Question

A cow is tied with a rope of length 14 m at the corner of a rectangular field of dimensions $20m\times 16m$, find the area of the field in which the cow can graze.

Answer 1

Area of the field in which the cow can graze
= πr²/4
= $\frac{\pi r^2}{4}$
= $\frac{196\pi }{4}$
= 49π
= 49 $\times \frac{22}{7}$
= 154 m²
Area of rectangular field
= l × b
= 20 × 16
= 320 m²
Area of the field in which the cow cannot graze
= Area of rectangular field - Area of the field in which the cow can graze
= 320 m² - 154 m²
= 166 m².