A cradle is h meters above the ground at the lowest position and H meters when it is at the highest point. If v is the maximum speed of the swing having total mass m, then the relation between h and H is:
A
mv2+h=H
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B
v22g+h=H
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C
v22g+2h=H
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D
v22g+H=h
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Solution
The correct option is Bv22g+h=H Using law of conservation of energy: P.E.highest+K.E.highest = P.E.Lowest + K.E.Lowest mgH+0=mgh+12mv2 ⇒H=h+v22g