A crest vertical curve joins two gradients of $+ 3$ % and $- 2$ % for a design speed of 80 km/h and the corresponding stopping sight distance of 120 m. The height of the driver's eye and the object above the road surface are $1.20$ m and $0.15$ m respectively . The curve length (which is less then stopping sight distance) to be provided is

163

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152

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120

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240

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Solution

The correct option is B $152$ m
When the curve length is less then stopping sight distance, then it is given by

$L = 2 S - \frac{4.4}{N}$
$= 2 \times 120 - \frac{4.4}{0.03 - (- 0.02)}$
$= 240 - 88 = 152$ m

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The correct option is B 152 mWhen the curve length is less then stopping sight distance, then it is given by L=2S−4.4N =2×120−4.40.03−(−0.02) =240−88=152 m

The correct option is B $152$ m
When the curve length is less then stopping sight distance, then it is given by

$L = 2 S - \frac{4.4}{N}$
$= 2 \times 120 - \frac{4.4}{0.03 - (- 0.02)}$
$= 240 - 88 = 152$ m