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Question

A cricket ball is hit with velocity 25 ms1, 60o above the horizontal. How far above the ground, ball passes over a field 50 m from the bat(consider the ball is struck very close to the ground)? (Take 3=1.7 and g=10 ms1)

A
6.6 m
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B
9.0 m
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C
11.6 m
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D
12.7 m
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Solution

The correct option is A 6.6 m
equation of trajectory is y=xtanθ12gx2u2(cosθ)2
substituting respective values will give us
y=50tan601210×502252(cos60)2
y=5 m

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