Question

A cricket ball of mass 100 g moving at a speed of 30 $m{s}^{-1}$ is brought to rest by a player in 0.03 s. Find the average force applied by the player.

Answer 1

Mass, m = 100g = 0.1 kg.
Initial velocity, u = 30 m/s.
Final velocity, v = 0.
Time, t = 0.03 s.
Acceleration = Change in velocity/time.
Or, a = (v – u)/t.
Or, a = (0 – 30)/ 0.03 = -1000 ms^-2.
Here, negative sign indicates retardation.
Now, Force = Mass x Acceleration
Or, F = (0.1) (1000) = 100 N