A cricket ball of mass $100 g$ moving with a velocity of $30 m / s$ is brought to rest by a player in $0.03 s e c$ find Rate of change in momentum of ball $.$

10 N

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20 N

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100 N

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None of these

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Solution

The correct option is C $100 N$
I guess the question is the rate of change in momentum
Mass $= 0.1 k g$
Initial Momentum $= m \times s p e e d$ $(u) = 0.1 \times 30 = 3$
Final Momentum= $m \times r e s t$ $(v) = 0.1 \times 0 = 0$
Change in Momentum= Final-Initial $= 0 - 3 = - 3$
Rate of change in momentum $= ($ change in momentum $) \div$ time taken
$= (- 3) \div 0.03$
$= - 100$
Hence,
option $(C)$ is correct answer.

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