Question

A cricket ball of mass $100g$ strikes the hand of player with a velocity of $20m{s}^{-1}$ and is brought to rest in $0.01s$. Calculate the force applied by the hand of the player.

• A. $2N$
• B. $2000N$
• C. $200N$
• D. $20N$

Answer 1

The correct option is C $200N$

Given mass of the ball as 100 g after converting to mks system it becomes 0.1 kg. As we know that acceleration is nothing but rate of change velocity and in this case we have initial velocity as 20m/s and final velocity as 0.

$a=(v-u)/t\Rightarrow$

$a=(0-20)/0.01=-2000m/s^2$

$F=m\times a\Rightarrow$

$F=0.1\times 2000=200N.$

The hand apply equal and opposite force of 200 N.