Question

A cricket ball of mass $100g$ strikes the hand of player with a velocity of $20m{s}^{-1}$ and is brought to rest in $0.01s$. Calculate the acceleration of the ball.

• A. $200m{s}^{-2}$
• B. $-20m{s}^{-2}$
• C. $-2m{s}^{-2}$
• D. $-2000m{s}^{-2}$

Answer 1

Answer: (D)

$-2000m{s}^{-2}$

As we know that acceleration is nothing but rate of change of velocity. We have,
$a=(v-u)/t$

$a=(0-20)/0.01=-2000m/s^2$

$a=-2000m/s^2$