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Question

A cricket ball of mass 200 gm moving with velocity 15 m/s is brought to rest by a player in 0.05 sec. What is the impulse of the ball and average force exerted by player?

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Solution

Impulse=change in momentum=m(vu)=0.2 (015)=3Ns
Average force=Impulse/Time=30.05=60 N

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