Question

A cricket ball of mass 500 gram moving with a velocity of 10 m/s hits a wall and returns with the same speed in the opposite direction. If the collision lasts for 0.1s , then find the force acting on the ball

Answer 1

$$\begin{gathered} changeinmomentum=m\left(v-u\right)=0.5\left[10-\left(-10\right)\right]=10Kgm{s}^{-1}. \\ thereforeforceontheball=\frac{changeinmometum}{timeofcollision}=\frac{10}{0.1}=100N. \end{gathered}$$