A cricket ball of radius R is exactly fitted in a cylindrical tin. The ratio of surface areas of cricket ball to the tin is

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Solution

Ratio of their areas= $\frac{4 π r^{2}}{2 π r (r + h)} = \frac{2 r}{r + h} = \frac{2}{3}$

(Height of cylinder = Diameter of ball fitted into it)

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A cricket ball of radius R is exactly fitted in a cylindrical tin. The ratio of surface areas of cricket ball to the tin is

Ratio of their areas=4 π r22 π r(r+h)=2rr+h=23 (Height of cylinder = Diameter of ball fitted into it)

Ratio of their areas= $\frac{4 π r^{2}}{2 π r (r + h)} = \frac{2 r}{r + h} = \frac{2}{3}$

(Height of cylinder = Diameter of ball fitted into it)