A cricket player catches a ball of mass $100 g$ and moving with a velocity of $25 {m s}^{- 1}$ . If the ball is caught in $0.1 s$ , the force of the blow exerted on the hand of the player is:

4 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

250 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is (C) $25 N$

We know,
$F = m a$
Or it can also be written as
Force( $F) = m \frac{d v}{d t}$
Since the ball is caught, hence final velocity is zero.

so here, $d v = 0 - 25 = - 25 m / s, d t = 0.1 s$

$∴ F = \frac{100}{1000} \times \frac{- 25}{0.1} = - 25 N$
Negative sign indicates that force is acting in opposite direction
Ans:(C)

Suggest Corrections

Similar questions

Q. A player caught a cricket ball of mass

150 g

moving at a rate of

20 m / s

. If the catching process is completed in

0.1 s

, the average force of the blow exerted by the ball on the hand of the player is equal to :

Q. A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s.If he catches it in 0.1 s, force of the blow exerted by ball on the player is.

A player caught a cricket ball of mass 150 gm moving at a rate of 20 m/s. If the catching process be completed in 0.1 s, then the force of the blow exerted by the ball on the hands of the player is

A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s. If the catching process is completed in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to

Q. A player caught a cricket ball of mass

150

g moving at a speed of

20

m/s. If the catching process is completed in

0.1

s, the force of the blow exerted by the ball on the hand of player is equal to

Join BYJU'S Learning Program

A cricket player catches a ball of mass 100g and moving with a velocity of 25ms−1. If the ball is caught in 0.1s, the force of the blow exerted on the hand of the player is:

The correct option is (C) 25NWe know, F=ma Or it can also be written as Force( F)=mdvdtSince the ball is caught, hence final velocity is zero.so here, dv=0−25=−25m/s,dt=0.1s∴F=1001000×−250.1=−25NNegative sign indicates that force is acting in opposite direction Ans:(C)

A cricket player catches a ball of mass $100 g$ and moving with a velocity of $25 {m s}^{- 1}$ . If the ball is caught in $0.1 s$ , the force of the blow exerted on the hand of the player is: